[git commit] hush: tweak comment, no code changes
vda.linux at googlemail.com
Tue Aug 14 09:04:58 UTC 2018
Signed-off-by: Denys Vlasenko <vda.linux at googlemail.com>
shell/hush.c | 8 ++++----
1 file changed, 4 insertions(+), 4 deletions(-)
diff --git a/shell/hush.c b/shell/hush.c
index 4b46752a3..881331c5b 100644
@@ -3162,7 +3162,7 @@ static int o_get_last_ptr(o_string *o, int n)
* code for partially-quoted strings.
* Unfortunately, if we want to match bash and ash behavior in all cases,
- * the logic can't be see as "shell-syntax argument is first transformed
+ * the logic can't be "shell-syntax argument is first transformed
* to a string, then globbed, and if globbing does not match anything,
* it is used verbatim". Here are two examples where it fails:
@@ -3171,14 +3171,14 @@ static int o_get_last_ptr(o_string *o, int n)
* The globbing can't be avoided (because of '?' at the end).
* The glob pattern is: b\\\*? - IOW, both \ and * are literals
* and are glob-escaped. If this does not match, bash/ash print b\*?
- * - IOW: they "unbackslash" the pattern.
+ * - IOW: they "unbackslash" the glob pattern.
* Now, look at this:
* v='\\\*'; echo b$v?
- * The glob pattern is the same here: b\\\*? - an unquoted $var expansion
+ * The glob pattern is the same here: b\\\*? - the unquoted $v expansion
* should be used as glob pattern with no changes. However, if glob
- * does not match, bash/ash print b\\\*? - NOT THE SAME as 1st example!
+ * does not match, bash/ash print b\\\*? - NOT THE SAME as first example!
* ash implements this by having an encoded representation of the word
* to glob, which IS NOT THE SAME as the glob pattern - it has more data.
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