Question: Does uclibc support NPTL TLS ?
Khem Raj
raj.khem at gmail.com
Thu May 28 02:00:34 UTC 2015
> On May 27, 2015, at 6:21 PM, Sheng Yong <shengyong1 at huawei.com> wrote:
>
> Hi,
>
> On 5/28/2015 3:18 AM, Rich Felker wrote:
>> On Wed, May 27, 2015 at 05:10:53PM +0800, Sheng Yong wrote:
>>> Hi,
>>>
>>> I encountered a problem when I test thread local storage
>>> on my arm board (kernel 3.10.77 and uclibc 0.99.3.2).
>>>
>>> Please let me know if I am doing something wrong for
>>> debugging TLS.
>>>
>>> on my x86 host machine:
>>> root at kernel-host:~> cat tls.c
>>> __thread int i =5;
>>>
>>> int
>>> main (int argc, char **argv)
>>> {
>>> return 0;
>>> }
>>>
>>> root at kernel-host:~> arm-linux-uclibceabi-gcc -o tls tls.c -g -lpthread
>>
>> If you add output (printf("%d", i)) to the program and actually run
>> it, does it work? It looks to me like the failure you're observing is
>> the inability of gdb to find the TLS while debugging, which is
>> separate from whether TLS is supported.
> I test it, it can printf the value of `i'. I don't know if there are any options
> that impact on gcc or gdb. I checked the configure log and compile log, there is
> no optins `-disable-tls' or `-no-tls' or the like.
>
> $ cat tls.c
> #include <stdio.h>
>
> __thread int i =5;
>
> int
> main (int argc, char **argv)
> {
> printf("%d\n", i);
> return 0;
> }
>
> sh-4.2# ./tls
> 5
>
Seems like gdb is not able to comprehend the TLS structure that uclibc is putting. So you need to investigate
that part, either gdb or libthread-db may be where the issue lies.
> thanks,
> Sheng
>
>>
>> Rich
>>
>>
>
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> uClibc at uclibc.org
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