Problems with output to console
Steven Scholz
steven.scholz at imc-berlin.de
Sat Dec 10 13:27:31 UTC 2005
Tito wrote:
> On Saturday 10 December 2005 11:41, Steven Scholz wrote:
>
>>Hi all,
>>
>>I have two different ARM based boards (different CPUs, both Linux
>>2.6.14) running BusyBox v1.00.
>>
>>I want a little application (started by a script that is started by
>>inittab) to output stuff using printf() on my serial console.
>>
>>foobar.c is
>>int main (void)
>>{
>> printf("Hello World (printf)!\n");
>> return 0;
>>}
>
> Hi, Just my 0.02 €.
In 0.01 € would be enough. Though you need 0.02 US$! ;-)
> Maybe something like:
>
> int main(void)
> {
> FILE *out;
>
> if((out = fopen(" /dev/ttyS0", "r+")) == NULL)
> return 1;
> fprintf(out, "test\n");
> fclose(out);
> return 0;
> }
>
> could be a workaround.
> But sure there is a better way.....
I am sure as well.
But I am not only looking for a workaround. I want to understand the
problem.
And as you might have guessed, I need this for debug outputs for my
application (which is of course a tiny little bit more complicated than
foobar.c ...)
So what happens, if I telnet into a closed box, kill the running
application and start it again? Right. Debug output is sent to serial
console, which I dont have then ... ;-)
So "stdout" is what I want. And "stdout" should be ttyS0 when started
from inittab (or from scripts that were started from inittab) started...
--
Steven
More information about the busybox
mailing list