[BusyBox] More init questions.
Rob Landley
rob at landley.net
Mon Jul 5 11:51:22 UTC 2004
Okay, I understand about a controlling tty, and I understand that each session
group can have at most one controlling tty.
However, the need to "steal back" the controlling tty from a terminated
process is a bit funky. (The current busybox "run()" code is a bit odd, to
say the least, but this bit of it's particularly odd.) Presumably, this is
something that isn't done simply by starting a new getty on the appropriate
terminal? (I looked at getty.c, and it's calling the same ioctl...)
This code triggers when the process that forks exited, but only if we waited
for that process to exit, not if it ran asynchronously. We call the ioctl to
associate the tty with a process that's about to exit, because previously the
tty was associated with a process that just exited?
Presumably, the tty might be associated with a child process of the one that
just exited. But until we fire up a new process on that terminal, why
exactly do we care? (Can we not open it again until we've done this? I can
go 'echo "boing" >> /dev/tty2' from the command line just fine...)
What exactly is the point of this "stealing the tty back" thing again? Why is
this init's job?
Rob
--
www.linucon.org: Linux Expo and Science Fiction Convention
October 8-10, 2004 in Austin Texas. (I'm the con chair.)
More information about the busybox
mailing list